FOR EXAMPLE:
If a fresh water sample at 20°C has a pH of 8.5 and the test result is 1.0 ppm as
Total Ammonia-Nitrogen:
1. The percentage from the table is 11.18% (or 0.1118).
2. 1 ppm Total Ammonia-Nitrogen x 0.1118 = 0.1118 ppm Unionized Ammonia-
Nitrogen.
3. Total Ammonia-Nitrogen 1.0000 ppm
Unionized Ammonia-Nitrogen - 0.1118 ppm
Ionized Ammonia-Nitrogen = 0.8882 ppm
Appendix
SMART3 Test Procedures 11.10 APPENDIX
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